There are n
rooms labeled from 0
to n - 1
and all the rooms are locked except for room 0
. Your goal is to visit all the rooms. However, you cannot enter a locked room without having its key.
When you visit a room, you may find a set of distinct keys in it. Each key has a number on it, denoting which room it unlocks, and you can take all of them with you to unlock the other rooms.
Given an array rooms
where rooms[i]
is the set of keys that you can obtain if you visited room i
, return true
if you can visit all the rooms, or false
otherwise.
Example 1:
Input: rooms = [[1],[2],[3],[]] Output: true Explanation: We visit room 0 and pick up key 1. We then visit room 1 and pick up key 2. We then visit room 2 and pick up key 3. We then visit room 3. Since we were able to visit every room, we return true.
Example 2:
Input: rooms = [[1,3],[3,0,1],[2],[0]] Output: false Explanation: We can not enter room number 2 since the only key that unlocks it is in that room.
Constraints:
n == rooms.length
2 <= n <= 1000
0 <= rooms[i].length <= 1000
1 <= sum(rooms[i].length) <= 3000
0 <= rooms[i][j] < n
rooms[i]
are unique.
class Solution {
public:
void dfs(vector>& rooms,vector& visited, int currRoom)
{
visited[currRoom]=true;
for(auto next:rooms[currRoom])
{
if(!visited[next])dfs(rooms,visited,next);
}
}
bool canVisitAllRooms(vector>& rooms) {
int n=rooms.size();
vector visited(n,false);
dfs(rooms,visited,0);
for(auto eachRoom:visited)
{
if(!eachRoom)return false;
}
return true;
}
};
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