Given an array of integers temperatures represents the daily temperatures, return an array answer such that answer[i] is the number of days you have to wait after the ith day to get a warmer temperature. If there is no future day for which this is possible, keep answer[i] == 0 instead.
Example 1:
Input: temperatures = [73,74,75,71,69,72,76,73] Output: [1,1,4,2,1,1,0,0]
Example 2:
Input: temperatures = [30,40,50,60] Output: [1,1,1,0]
Example 3:
Input: temperatures = [30,60,90] Output: [1,1,0]
Constraints:
1 <= temperatures.length <= 10530 <= temperatures[i] <= 100
class Solution {
public:
vector<int> dailyTemperatures(vector<int>& temperatures) {
int n=temperatures.size();
vector<int> ans(n,0);
stack<int> st;
for(int i=n-1; i>=0; i--)
{
while(!st.empty() and temperatures[st.top()]<=temperatures[i])st.pop();
if(!st.empty())ans[i]=st.top()-i;
st.push(i);
}
return ans;
}
};
Office:- 660, Sector 14A, Vasundhara, Ghaziabad, Uttar Pradesh - 201012, India
