### LeetCode Challenge #2089. Find Target Indices After Sorting Array

You are given a 0-indexed integer array `nums` and a target element `target`.

target index is an index `i` such that `nums[i] == target`.

Return a list of the target indices of `nums` after sorting `nums` in non-decreasing order. If there are no target indices, return an empty list. The returned list must be sorted in increasing order.

Example 1:

```Input: nums = [1,2,5,2,3], target = 2
Output: [1,2]
Explanation: After sorting, nums is [1,2,2,3,5].
The indices where nums[i] == 2 are 1 and 2.
```

Example 2:

```Input: nums = [1,2,5,2,3], target = 3
Output: 
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 3 is 3.
```

Example 3:

```Input: nums = [1,2,5,2,3], target = 5
Output: 
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 5 is 4.
```

Constraints:

• `1 <= nums.length <= 100`
• `1 <= nums[i], target <= 100`
##### Video Solution
###### Java Solution
```				```
class Solution {
public List<Integer> targetIndices(int[] nums, int target) {
int num = 0 ;
int tcount = 0 ;

for(int ele : nums ){
if(ele == target){
tcount++;
}else if ( ele < target){
num++;
}
}

List<Integer> ans = new ArrayList<>();

while(tcount>0){