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<= operator instead of the .issubset() method.Syntax –
set_name.issubset(iterable)
Parameter –
Example 1-
A={1,2,3,4,5,6,7,8,9}
B={1,3,5,7,9}
print("Set A:",A)
print("Set B:",B)
print("Set B is a subset of Set A:",B.issubset(A))
# Output -
# Set A: {1, 2, 3, 4, 5, 6, 7, 8, 9}
# Set B: {1, 3, 5, 7, 9}
# Set B is a subset of Set A: True
Example 2-
s={'e','d','S','l','a','s','h'}
s1={'a','b','c','d','e','f','g','h','s'}
print("Set 1:",s)
print("Set 2:",s1)
print("Set s1 is a subset of set s:",s1.issubset(s))
# Output -
# Set 1: {'e', 'l', 'h', 'a', 's', 'd', 'S'}
# Set 2: {'b', 'e', 'f', 'g', 'h', 'a', 's', 'd', 'c'}
# Set s1 is not a subset of set s: False
issubset() method with the list –
Example 3-
l=['Anurag','Nitin','Niketan']
s={'Anurag'}
print("List :",l)
print("Set :",s)
print("Set s is a subset of list l:",s.issubset(l))
# Output -
# List : ['Anurag', 'Nitin', 'Niketan']
# Set : {'Anurag'}
# Set s is a subset of list l: True
how to check whether a set is a subset of another set without using any built-in method –
Example 4-
set1 = {1, 2, 3}
set2 = {1, 2, 3, 4, 5}
print("set1 :",set1)
print("set2 :",set2)
is_subset = set1 <= set2
print("set1 is subset of set2:",is_subset)
# Output -
# set1 : {1, 2, 3}
# set2 : {1, 2, 3, 4, 5}
# set1 is subset of set2: True
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