Day 3 of 100 Days LeetCode Challenge

LeetCode Challenge #509. Fibonacci Number

The Fibonacci numbers, commonly denoted F(n) form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from 0 and 1. That is,

F(0) = 0, F(1) = 1
F(n) = F(n - 1) + F(n - 2), for n > 1.

Given n, calculate F(n).

 

Example 1:

Input: n = 2
Output: 1
Explanation: F(2) = F(1) + F(0) = 1 + 0 = 1.

Example 2:

Input: n = 3
Output: 2
Explanation: F(3) = F(2) + F(1) = 1 + 1 = 2.

Example 3:

Input: n = 4
Output: 3
Explanation: F(4) = F(3) + F(2) = 2 + 1 = 3.

 

Constraints:

  • 0 <= n <= 30
Video Solution
Java Solution
				
					class Solution {
    public int fib(int n) {

     if(n==0){
            return 0 ;
        }else if ( n==1){
            return 1 ;
        }

        int ft = 0 ;
        int st = 1 ;

        for(int i=1 ; i<=n;i++){
            int tt = ft + st ;
            ft = st ;
            st = tt ;
        }

        return ft ;
    }
}
				
			
Flowchart of Java Solution
Flowchart of LeetCode Problem 509 - Fibonacci Number
Python Solution
				
					def fib(self, n: int) -> int:
        if n <= 1:
            return n
        else:
            return self.fib(n - 1) + self.fib(n - 2)
				
			

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