Day 8 of 100 Days LeetCode Challenge

LeetCode Challenge #1464. Maximum Product of Two Elements in an Array

Given the array of integers nums, you will choose two different indices i and j of that array. Return the maximum value of (nums[i]-1)*(nums[j]-1).

 

Example 1:

Input: nums = [3,4,5,2]
Output: 12 
Explanation: If you choose the indices i=1 and j=2 (indexed from 0), you will get the maximum value, that is, (nums[1]-1)*(nums[2]-1) = (4-1)*(5-1) = 3*4 = 12. 

Example 2:

Input: nums = [1,5,4,5]
Output: 16
Explanation: Choosing the indices i=1 and j=3 (indexed from 0), you will get the maximum value of (5-1)*(5-1) = 16.

Example 3:

Input: nums = [3,7]
Output: 12

 

Constraints:

  • 2 <= nums.length <= 500
  • 1 <= nums[i] <= 10^3
Video Solution
Java Solution
				
					class Solution {
    public int maxProduct(int[] nums) {
        int smax = -1 ;
        int max = -1 ;

        for(int i=0;i<nums.length;i++){
            if(max<nums[i]){
                smax = max ;
                max = nums[i];
            }else if(smax<nums[i]){
                smax = nums[i];
            }
        }

        int ans = (max-1) * (smax-1);
        return ans;
    }
}
				
			

Happy Coding with edSlash