Given 3 positives numbers a, b and c. Return the minimum flips required in some bits of a and b to make ( a OR b == c ). (bitwise OR operation).
Flip operation consists of change any single bit 1 to 0 or change the bit 0 to 1 in their binary representation.
Example 1:
Input: a = 2, b = 6, c = 5 Output: 3 Explanation: After flips a = 1 , b = 4 , c = 5 such that (aORb==c)
Example 2:
Input: a = 4, b = 2, c = 7 Output: 1
Example 3:
Input: a = 1, b = 2, c = 3 Output: 0
Constraints:
1 <= a <= 10^91 <= b <= 10^91 <= c <= 10^9
class Solution {
public:
int minFlips(int a, int b, int c) {
int p,q,r,count=0;
for(int i=0; i<32; i++)
{
p=a&(1<<i);
q=b&(1<<i);
r=c&(1<<i);
if(r==0)
{
if(p!=0 and q==0)count+=1;
else if(p==0 and q!=0)count+=1;
else if(p!=0 and q!=0)count+=2;
}
else{
if(p==0 and q==0)count+=1;
}
}
return count;
}
};
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