Given the head
of a linked list and an integer val
, remove all the nodes of the linked list that has Node.val == val
, and return the new head.
Example 1:
Input: head = [1,2,6,3,4,5,6], val = 6 Output: [1,2,3,4,5]
Example 2:
Input: head = [], val = 1 Output: []
Example 3:
Input: head = [7,7,7,7], val = 7 Output: []
Constraints:
[0, 104]
.1 <= Node.val <= 50
0 <= val <= 50
class Solution {
public ListNode removeElements(ListNode head, int val) {
if(head == null){
return null;
}
ListNode dummy = new ListNode(-1);
dummy.next = head ;
ListNode curr = dummy ;
while(curr.next!=null){
if(curr.next.val==val){
curr.next = curr.next.next;
}else{
curr = curr.next;
}
}
return dummy.next;
}
}
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