There is a singly-linked list head
and we want to delete a node node
in it.
You are given the node to be deleted node
. You will not be given access to the first node of head
.
All the values of the linked list are unique, and it is guaranteed that the given node node
is not the last node in the linked list.
Delete the given node. Note that by deleting the node, we do not mean removing it from memory. We mean:
node
should be in the same order.node
should be in the same order.Custom testing:
head
and the node to be given node
. node
should not be the last node of the list and should be an actual node in the list.
Example 1:
Input: head = [4,5,1,9], node = 5 Output: [4,1,9] Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.
Example 2:
Input: head = [4,5,1,9], node = 1 Output: [4,5,9] Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.
Constraints:
[2, 1000]
.-1000 <= Node.val <= 1000
node
to be deleted is in the list and is not a tail node.
class Solution {
public void deleteNode(ListNode node) {
node.val = node.next.val;
node.next = node.next.next;
}
}
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